q=%26%2340%E7%BE%8E%26%2341%E6%9D%8E%2BH.%E6%8B%89%E5%BE%B7%E9%B2%8D%26%2340Lee%2BH.Radebaugh%26%2341&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
(美)李+H.拉德鲍(Lee+H.Radebaugh)